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x2-4x+1=0 এবং a2+1a2=5 দুইটি বীজগাণিতিক সমীকরণ।n ^ 2 + 13n - 48
p4+p2+1
=(p2)2+2p2.1+12-p2
=(p2+1)2-p2
=(p2+1+p)(p2+1-p)
=(p2+p+1)(p2-p+1)
a3+8
a3+8=(a)3+(2)3=(a+2)(a)2-a.2+(2)2=(a+2)(a2-2a+4)
8x3+343
8x3+343=(2x)3+(7)3=(2x+7)(2x)2-2x.7+(7)2=(2x+7)(4x2-14x+49)
8a4+27ab3
8a4+27ab3=a(8a3+27b3)=a{(2a)3+(3b)3}=a(2a+3b){(2a)2-2a.3b+(3b)2}=a(2a+3b)(4a2-6ab+9b2)
8x3+1
8x3+1=(2x)3+(1)3
=(2x+1){(2x)2-2x.1+(1)2}=(2x+1)(4x2-2x+1)
64a3-125b3
64a3-1525b3
=(4a)3-(5b)3
=(4a-5b){(4a)2+4a.5b+(5b)2}
=(4a-5b)(16a2+20ab+25b2)
729a3-64b3c6
729a3-64b3c6=(9a)3-(4bc2)3
=(9a-4bc2){(9a)2+9a.4bc2+(4bc2)2}=(9a-4bc2)(81a2+36abc2+16b2c4)
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